给定一个不含重复数字的数组 nums
,返回其 所有可能的全排列 。你可以 按任意顺序 返回答案。
示例 1:
输入:nums = [1,2,3] 输出:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
示例 2:
输入:nums = [0,1] 输出:[[0,1],[1,0]]
示例 3:
输入:nums = [1] 输出:[[1]]
提示:
1 <= nums.length <= 6
-10 <= nums[i] <= 10
nums
中的所有整数 互不相同
题解:
回溯法:
func permute(nums []int) [][]int {
var path []int
var result [][]int
var used map[int]bool
var backtracking func(nums []int, jumpIndex int)
backtracking = func(nums []int, jumpIndex int) {
if len(path) == len(nums) {
tmp := make([]int, len(path))
copy(tmp, path)
result = append(result, tmp)
return
}
for i := 0; i < len(nums); i++ {
if used[nums[i]] {
continue
}
used[nums[i]] = true
path = append(path, nums[i])
backtracking(nums, i)
used[nums[i]] = false
path = path[:len(path)-1]
}
}
used = make(map[int]bool, len(nums))
backtracking(nums, 0)
return result
}
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